2x^2-2x-40/2x-10

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Solution for 2x^2-2x-40/2x-10 equation: 


x in (-oo:+oo)

2*x^2-(2*x)-((40/2)*x)-10 = 0

2*x^2-2*x-20*x-10 = 0

2*x^2-22*x-10 = 0

DELTA = (-22)^2-(-10*2*4)

DELTA = 564

DELTA > 0

x = (564^(1/2)+22)/(2*2) or x = (22-564^(1/2))/(2*2)

x = (2*141^(1/2)+22)/4 or x = (22-2*141^(1/2))/4

x in { (22-2*141^(1/2))/4, (2*141^(1/2)+22)/4 }

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